0,001x^2+5,6x-4500=0

Solution for 0,001x^2+5,6x-4500=0 equation:

0.001x^2+5.6x-4500=0

a = 0.001; b = 5.6; c = -4500;
Δ = b2-4ac
Δ = 5.62-4·0.001·(-4500)
Δ = 49.36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5.6)-\sqrt{49.36}}{2*0.001}=\frac{-5.6-\sqrt{49.36}}{0.002}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5.6)+\sqrt{49.36}}{2*0.001}=\frac{-5.6+\sqrt{49.36}}{0.002}
$